What are the odds of rolling double sixes twice in a row?

The odds of rolling double sixes twice in a row with two standard dice are 1 in 1,296, calculated by multiplying the 1/36 chance of the first roll by the 1/36 chance of the second roll ( 1 / 36 × 1 / 36 = 1 / 1296 1 / 3 6 × 1 / 3 6 = 1 / 1 2 9 6 ); it's the same as rolling a six, four times consecutively (1/6 x 1/6 x 1/6 x 1/6) because each roll is an independent event.
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What are the odds of rolling 2 6's in a row?

the probability of getting 2 sixes in row is 1/36, but these are independant probabilities, to get a second six given the first is 6, this is bayes and i must reverse the final result which should be 1/42 to get the number which i want, 42.
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What are the odds of rolling doubles 7 times in a row?

She rolled seven doubles in a row. Next roll 5 and 2, ninth roll double again. Odds are one in 1.6 trillion for seven in a row.
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How to calculate the probability of something happening twice in a row?

For example, if we roll a die and then roll it again, the outcome of the second roll is independent from the outcome of the first event. To determine the probability of two independent events, and , both occurring, we multiply the probabilities of each of the two events together: P ( A ) × P ( B ) = P ( A a n d B ) .
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What are the odds of a double six?

When two fair six-sided dice (I presume those additional criteria were intended to be in the question) are rolled, the probability that a double 6 will occur is 1/36, so the probability that a double 6 will fail to occur is 35/36.
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Probability of Rolling Dice

How do you calculate doublet probability?

Calculating the Probability of a Doublet

Since there are 36 possible outcomes when rolling two dice (6 sides on the first die multiplied by 6 sides on the second die), the probability of rolling a doublet is: P(Doublet) = Number of Doublets / Total Outcomes. P(Doublet) = 6 / 36 = 1/6.
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What are the odds of winning a 50/50 7 times in a row?

* The binomial distribution formula is: P(X = k) = C(n, k) * p^k * (1-p)^(n-k) * In our case: * n = 50 (number of trials) * k = 7 (number of successes, i.e., drawing the same card) * p = 1/78 (probability of success on each trial) * Using a calculator or statistical software to calculate this probability will give you ...
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How rare is it to get 2 1% in a row?

You can trick yourself into thinking you've gotten something rarer than you actually have this way. For the probability of getting two specific 1% drops, one after the other, assuming one roll doesn't effect the next, it would be 1%x1% = 0.01*0.01 = 0.0001 = 0.01%.
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What are the odds of a 10% chance happening twice in a row?

For things like that you just multiply the odds together, so 1/10 * 1/10, or 1/100 chance for twice in a row.
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What are the odds of rolling a 7 6 times in a row?

Out of the 36 combinations that come up with 2 dice, 6 of them add up to 7 (in fact, it's the most likely result, because there are more ways to make 7 than any other number). So your chance of rolling a 7 on any given turn is 1/6. To do that 6 times in a row would be (1/6)6 = 1/46,656.
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What are some common probability mistakes?

Not understanding when events are independent

If you flip a fair coin 1,000,000 times and get 1,000,000 heads in a row, the probability of getting heads on the next flip is still 1/2. The very definition of statistical independence between two events is that the outcome of one has no effect on the outcome of another.”
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What if you roll a 7 in craps?

Rolling a 7 in craps is a big deal, but what happens depends on when it's rolled: on the first "come-out" roll, a 7 wins for Pass Line bettors; but once a "point" (4, 5, 6, 8, 9, 10) is set, a 7 "sevens out," causing Pass Line bets to lose and ending the shooter's turn, while "Don't Pass" or "Don't Come" bets win, and other bets like "Any 7" pay out immediately. 
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What are double sixes called in dice?

Double sixes (6-6) are most commonly called Boxcars in dice games like craps, named for looking like railroad cars; they're also known as Midnight (totaling 12) or sometimes "All the Dots," especially in craps where it's a significant roll.
 
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What are the odds of rolling a 7 four times in a row?

Each outcome is 1/36, but there are 6 ways to make 7 (6+1, 5+2, 4+3, 3+4, 2+5, 1+6), so the chance of rolling one 7 is 6/36 = 1/6. The rolls are independent, so rolling four in a row is 1/64 = 1/1296.
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What are the odds of rolling heads 6 times in a row?

The odds of getting 6 heads in a row with a fair coin are 1 in 64, or about 1.56%, because each flip has 2 outcomes, so there are 26=642 to the sixth power equals 6426=64 total possibilities, and only one is all heads (HHHHHH). This remains the same for any specific sequence of 6 flips, as each flip is independent. 
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Is a coin flip actually 51/49?

Yes, a coin flip isn't perfectly 50/50; it's slightly biased towards the side that starts facing up, landing on that same side about 51% of the time and the opposite side 49%. This tiny bias happens because a coin tends to wobble off-center during a natural flip, spending slightly more time in the air with its initial upward face on top.
 
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What are the odds of getting heads 20 times in a row?

On the other hand, the odds of a fair coin coming up "heads" 20 times in a row is less than 1 in 1,000,000.
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What are the odds of hitting a 30% chance 6 times in a row?

For her specifically the probability is 0.3 ^ 6 = 0.000729 = 0.0729 % .
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What are the odds of losing 50/50 8 times in a row?

Ever since then i lost 8 more and apparently that has a 0,390625% chance to happen.
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What are the odds of winning 5 coinflips in a row?

The odds of winning 5 coin flips in a row (e.g., getting 5 heads) are 1 in 32, or about 3.125%, because each flip has a 1/2 chance, and you multiply these probabilities together: (1/2) x (1/2) x (1/2) x (1/2) x (1/2) = 1/32. The odds are the same for any specific sequence, like five tails, but if you just want any five in a row to be the same (all heads or all tails), the odds are 1 in 16. 
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What are the odds of rolling doubles with 3 dice?

Probability of all three dice the same = 1×1/6×1/6=1/36. Probability of no dice the same = 1×5/6×4/6=20/36. Probability of a pair = 1−1/36−20/36=15/36.
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How to find probability of 2 spinners?

Multiply the probabilities just calculated for each individual spinner together to find the probability of getting any specific combination of outcomes from spinning the arrows on both spinners. In the example, you would multiply 1/4 by 1/3 to obtain 1/12.
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What is the probability of a doublet?

Number of all possible outcomes= 36. The doublets are (1,1),(2,2),(3,3),(4,4),(5,5),(6,6). Their number is 6. P(getting a doublet) = 6 36 = 1 6 .
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